(PHP 4 >= 4.0.0)
in_array -- Return
TRUE if a value exists in an array
Description
bool
in_array ( mixed needle, array haystack [, bool strict])
Searches haystack for
needle and returns TRUE
if it is found in the array, FALSE otherwise.
If the third parameter strict is set to
TRUE then the in_array()
will also check the types of
the needle in the haystack.
Note:
If needle is a string, the comparison is done in
a case-sensitive manner.
Note:
In PHP versions before 4.2.0 needle was not
allowed to be an array.
Example 1. in_array() example $os = array ("Mac", "NT", "Irix", "Linux");
if (in_array ("Irix", $os)) {
print "Got Irix";
}
if (in_array ("mac", $os)) {
print "Got mac";
} |
The second condition fails because in_array()
is case-sensitive, so the program above will display:
|
Example 2. in_array() with strict example <?php
$a = array('1.10', 12.4, 1.13);
if (in_array('12.4', $a, TRUE))
echo "'12.4' found with strict check\n";
if (in_array(1.13, $a, TRUE))
echo "1.13 found with strict check\n";
?> |
This will display:
1.13 found with strict check |
|
Example 3. in_array() with an array as needle <?php
$a = array(array('p', 'h'), array('p', 'r'), 'o');
if (in_array(array ('p', 'h'), $a))
echo "'ph' is found\n";
if (in_array(array ('f', 'i'), $a))
echo "'fi' is not found\n";
if (in_array('o', $a))
echo "'o' is found\n";
?>
// This will output:
'ph' is found
'o' is found |
|
See also array_search().